7.t.27 write eq for a sinusiol graph

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The equation for a sinusoidal graph with an amplitude of -3, a period of 2π/3, and a phase shift of -π/4 is expressed as y = -3sin(ωx - φ). To determine ω, use the formula T = 2π/ω, leading to ω = 3. The phase shift φ can be calculated using φ = -π/4, resulting in the final equation y = -3sin(3x + π/4).

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Write an equation for a sinusiol graph with the following
\quad $A=-3$ \quad period $=\dfrac{2\pi}{3}$ phase shift $=-\dfrac{\pi}{4}$
For the graphs of $y=A\sin(\omega x - \phi)$ or $y=A\cos(\omega x - \phi),\omega>0$
Amplitude $=|A|$ \quad Period $=T=\dfrac{2\pi}{\omega}$ \quad Phase shift $=\dfrac{\phi}{\omega}$
$y=-3\sin(\omega x - \phi)$

ok, I still get ? with these sinusol graphs
 
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You have the equations! Solve for [math]T = 2 \pi / 3[/math] so solve for [math]\omega[/math]. Then find [math]\phi[/math].

-Dan
 
topsquark said:
You have the equations! Solve for [math]T = 2 \pi / 3[/math] so solve for [math]\omega[/math]. Then find [math]\phi[/math].

-Dan

ok I think this is it ... typos maybe
$
Screenshot 2022-02-09 11.22.48 AM.png
 
Last edited:

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