A ball is thrown up solve for variables, kenimatics

In summary, the launch angle of a ball shot from level ground with a certain speed v0 determines both the time of flight t and the minimum speed vmin the ball will have during its flight. This means that t and vmin can be related to each other. Additionally, at a certain angle, the ball will have a maximum possible time of flight, tmax. To find the ratio of vmin to v0, a formula can be used involving t, tmax, and the acceleration due to gravity g. However, a simplified answer of vmin/v0 = cos(theta) may not be accepted by the computer. It is recommended to refer to examples in a kinematics book for further understanding.
  • #1
Rower93
1
0
A ball is to be shot from level ground with a certain speed v0 at various angles θ. The launch angle determines both the time of flight t and the minimum speed vmin the ball will have during its flight, which means they can be related to each other. At some angle, the ball will have a maximum possible time of flight. Call this time tmax. Find a formula which gives the ratio of vmin to v0 in terms of t, tmax, and g.


I honestly do not know where to go with this one, it has stumped my roommate and i for over an hour!


It is asking for the answer in a ratio of vmin/v0

if simplified you can get an answer of vmin/v0 = v0 cos(theta)/v0 = cos(theta)

The computer does not accept this as a valid response.

Any help is appreciated,
Cheers!
 
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  • #2
You need to read the book and think of how the example problems in kinematics relates to this.

Break it into two parts the ball motion going up and then coming down and the motion of the ball going horizontally.
 

1. What is the formula for calculating the height of a ball thrown up?

The formula for calculating the height of a ball thrown up is h = v0t - 1/2gt2, where h is the height, v0 is the initial velocity, g is the acceleration due to gravity (9.8 m/s2), and t is the time in seconds.

2. How do you solve for the initial velocity of a ball thrown up?

To solve for the initial velocity of a ball thrown up, you can use the formula v0 = h/t + 1/2gt, where v0 is the initial velocity, h is the height, g is the acceleration due to gravity, and t is the time in seconds.

3. What is the maximum height a ball can reach when thrown up?

The maximum height a ball can reach when thrown up depends on the initial velocity and the angle at which it is thrown. Assuming no air resistance, the maximum height can be calculated using the formula hmax = v02/2g, where hmax is the maximum height, v0 is the initial velocity, and g is the acceleration due to gravity.

4. How does air resistance affect the motion of a ball thrown up?

Air resistance can decrease the maximum height and increase the time it takes for a ball to reach its maximum height when thrown up. It also affects the trajectory of the ball, causing it to follow a curved path rather than a straight one. The extent to which air resistance affects the motion of the ball depends on factors such as the size and shape of the ball, the density of the air, and the initial velocity of the ball.

5. Can the kinematic equations be used to solve for the motion of a ball thrown up?

Yes, the kinematic equations can be used to solve for the motion of a ball thrown up. These equations, which include formulas for displacement, velocity, and acceleration, can be used to accurately describe the motion of an object, such as a ball thrown up, under the influence of gravity.

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