A projectile kinematic in 2 d problem using baskeballs?

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SUMMARY

The discussion focuses on solving a projectile motion problem involving a basketball shot. The basketball is released from a height of 2.20m and must reach a basket at 3.05m, with a horizontal distance of 5.90m. The player shoots at a 35.0° angle, and the task is to determine the range of initial speeds (vmin, vmax) required to make the basket, accounting for a horizontal accuracy of ±0.22m. Key equations used include the horizontal motion equation Xf = X0 + v0t and the vertical motion components V0x = V0 cos(35) and V0y = V0 sin(35).

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  • Understanding of projectile motion principles
  • Knowledge of trigonometric functions (sine and cosine)
  • Familiarity with kinematic equations
  • Basic algebra for solving equations
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  • Determine the initial velocity required to reach the basket height
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Homework Statement



A basketball leaves a player's hands at a height of 2.20m above the floor. The basket is 3.05m above the floor. The player likes to shoot the ball at a 35.0∘ angle.If the shot is made from a horizontal distance of 5.90m and must be accurate to ±0.22m (horizontally), what is the range of initial speeds allowed to make the basket?
Express your answers using thre significant figures separated by a comma.
Answer in vmin, vmax = m/s

x0=0
yo=0
xf=5.90 m ±0.22m
ax=0 m/s^2
ay=-9.8 m/s^2

Homework Equations



Xf=X0+v0t


The Attempt at a Solution



am I solving for V0x=V0 cos(35)?
& Voy=V0sin (35)


so I did
Xf=X0+v0t
xf=x0 + (vo vcos 35)t
xf= vo cos (35)t
t= xf/ vo cos(35)t

I am just confused that this point.
 
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You covered the horizontal part, that's fine. What about the vertical motion?
 

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