A double-slit (Young experiment) problem

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Homework Help Overview

The problem involves Young's double-slit interference experiment, focusing on the conditions for destructive interference between two light waves represented by their equations. The original poster attempts to find possible values of the phase difference, Φ, under the condition of destructive interference at a specific point on the screen.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss different methods to derive the phase difference, including using the condition for destructive interference and summing wave functions. Questions arise regarding the validity of the conditions used and the implications of the results obtained.

Discussion Status

The discussion is active, with participants sharing their reasoning and questioning each other's approaches. Some guidance has been offered regarding the conditions for destructive interference, and there is an exploration of different interpretations of the results.

Contextual Notes

Participants are navigating the complexities of phase differences and the conditions required for consistent destructive interference, indicating potential gaps in understanding or assumptions about the wave behavior.

physicist10
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Homework Statement



In Young's double-slit interference experiment with light of wavelength \lambda, two light waves come from the slits and are superposed at the point P on the screen. These waves have the following forms:

E1 = E0 sin(wt + π/4)
E2 = E0 sin(wt + Φ)

Find the possible values of Φ if we have destructive interference at the point P.

Homework Equations



27baa5fb481ec2dcaf6cbb38b56f2570.png


The Attempt at a Solution



I attempted the problem two different ways and I had two different results.

Φ = 2kπ - π/4
Φ = 2kπ + 5π/4

Help me out please.
 
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Can you show us how you got that?
 
Phase difference is Φ - π/4.

So d/λ = (Φ - π/4)/2π

d = (2k+1)/2 λ for destructive interference

So, (2k+1)/2 λ = (Φ - π/4)/2π λ

Φ = 2kπ + 5π/4

-------------

The second way, I added 2 wave functions together and I equated the expression to zero.

I found Φ = 2kπ - π/4
 
How did you arrive at Φ = 2kπ - π/4?
 
Let's see. The sum of the two waves is:

E = 2E0 sin(wt + π/8 + Φ/2) cos(π/8 - Φ/2) = 0

That is satisfied when

wt + π/8 + Φ/2 = kπ

wt=2πft=2π, so we can drop it.

Φ = 2kπ - π/4
 
physicist10 said:
Let's see. The sum of the two waves is:

E = 2E0 sin(wt + π/8 + Φ/2) cos(π/8 - Φ/2) = 0

That is satisfied when

wt + π/8 + Φ/2 = kπ

wt=2πft=2π, so we can drop it.

Φ = 2kπ - π/4

The condition E=0 must be satisfied at ALL TIME for destructive pattern, and the bold line is not true at all time.
Find another condition :wink:
 
Hmm, thanks hikaru. How can I proceed? I have no idea.
 
What about cos(π/8 - Φ/2)?
 
Oh yes, I found it now. I must equate the cosine term (cos(π/8 - Φ/2)) to zero. But why exactly?
 
  • #10
Because of this: "The condition E=0 must be satisfied at ALL TIME for destructive pattern" :wink:
 

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