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I am solving for the height of a tank as a function of time.

The tank has a constant inflow of a and is subjected to small fluctuation of bsin(wt).

So the inflow is simply a+bsin(wt).

The outflow should be proportional to the square root of the height, H.

So outflow = c*sqrt(H)

Therefore the below differential equation is obtained with k=the area of the tank:

[tex]\frac{a+bsinwt-c\sqrt{H}}{k}=\frac{dH}{dt}[/tex]

but the problem is that I don't know how to solve this ODE...

Can anyone solve the problem?

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# A math or a simple fluid problem?

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