A problem on arithmetic progressions.

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The discussion focuses on solving arithmetic progressions, specifically finding the common difference, the value of Z, and the first term of the sequence. The common difference (d) is calculated using the equation 22 + 4d = 42, resulting in d = 5. The value of Z is determined to be 57 by adding three times the common difference to 42. Finally, the first term (a1) of the sequence is found to be 12 using the formula an = a1 + (n – 1)d.

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Okay, So far I have seen and know to find the common difference of arithmetic terms using the consecutive terms. But this progression looks different (Shake)

Find the common difference , Value of Z and the first term of it.

Many Thanks (Happy)
 

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Since 42 is four terms after 22 we must have 22 + 4d = 42, where d is the common difference. Can you solve for d and use that value to complete the other questions?
 
greg1313 said:
Since 42 is four terms after 22 we must have 22 + 4d = 42, where d is the common difference. Can you solve for d and use that value to complete the other questions?

Using the equation 22 + 4d = 42; d = 5;

Correct?

Now is there another way to find this,My method was to add 3 times the common difference.

Z=42+(5*3)
Z=42+15
Z=42+15
Z=57

To find the first term of the sequence , using the formula

an = a1 + (n – 1)d
57 = a1 + (10 – 1)5
57 = a1 + 45
57-45=a1
12=a1
 
Last edited:
Your value for d is wrong but everything else looks correct.
 
I see you've edited your post. d = 5 is correct.
 
Thank you ;)
 
mathlearn said:
Using the equation 22 + 4d = 42; d = 5;

Correct?

Now is there another way to find this,My method was to add 3 times the common difference.

Z=42+(5*3)
Z=42+15
Z=42+15
Z=57

To find the first term of the sequence , using the formula

an = a1 + (n – 1)d
57 = a1 + (10 – 1)5
57 = a1 + 45
57-45=a1
12=a1

Well done! :)
 

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