MHB A problem on arithmetic progressions.

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The discussion focuses on solving a problem involving arithmetic progressions, specifically finding the common difference, the value of Z, and the first term. The common difference (d) is determined using the equation 22 + 4d = 42, resulting in d = 5. The value of Z is calculated as 57 by adding three times the common difference to 42. Finally, the first term of the sequence is found to be 12 using the formula an = a1 + (n – 1)d. The calculations are confirmed as correct, leading to a successful resolution of the problem.
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Okay, So far I have seen and know to find the common difference of arithmetic terms using the consecutive terms. But this progression looks different (Shake)

Find the common difference , Value of Z and the first term of it.

Many Thanks (Happy)
 

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Since 42 is four terms after 22 we must have 22 + 4d = 42, where d is the common difference. Can you solve for d and use that value to complete the other questions?
 
greg1313 said:
Since 42 is four terms after 22 we must have 22 + 4d = 42, where d is the common difference. Can you solve for d and use that value to complete the other questions?

Using the equation 22 + 4d = 42; d = 5;

Correct?

Now is there another way to find this,My method was to add 3 times the common difference.

Z=42+(5*3)
Z=42+15
Z=42+15
Z=57

To find the first term of the sequence , using the formula

an = a1 + (n – 1)d
57 = a1 + (10 – 1)5
57 = a1 + 45
57-45=a1
12=a1
 
Last edited:
Your value for d is wrong but everything else looks correct.
 
I see you've edited your post. d = 5 is correct.
 
Thank you ;)
 
mathlearn said:
Using the equation 22 + 4d = 42; d = 5;

Correct?

Now is there another way to find this,My method was to add 3 times the common difference.

Z=42+(5*3)
Z=42+15
Z=42+15
Z=57

To find the first term of the sequence , using the formula

an = a1 + (n – 1)d
57 = a1 + (10 – 1)5
57 = a1 + 45
57-45=a1
12=a1

Well done! :)
 
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