zetafunction
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using an exponential regulator [tex]exp(-\epsilon n)[/tex] the sum
[tex]1+2+3+4+5+6+7+...= -1/12+ 1/\epsilon^{2}[/tex]
and for Casimir effect [tex]1+8+27+64+125+...= -1/120+ 1/\epsilon^{4}[/tex]
can i simply remove in the calculations of divergent series 1+2+3+4+5.. and similar the epsilon terms imposing renormalization conditions ??
how about for the rest of sums [tex]1+2^{m}+3^{m}+...= \zeta (-m) + 1/\epsilon ^{m+1}[/tex]
if i introducte a power regulator [tex]n^{-s}[/tex] in the limit s-->0+ i would get
[tex]\zeta(s-m)=\zeta(-m)[/tex] but i am not sure, why this work
for example in the definition of a functional determinant (in differential geommetry )
[tex]\prod_{i} \lambda_{i}[/tex] apparently there is no divergent term proportional to [tex]log(\epsilon)[/tex] as one would expect since the product is divergent
[tex]1+2+3+4+5+6+7+...= -1/12+ 1/\epsilon^{2}[/tex]
and for Casimir effect [tex]1+8+27+64+125+...= -1/120+ 1/\epsilon^{4}[/tex]
can i simply remove in the calculations of divergent series 1+2+3+4+5.. and similar the epsilon terms imposing renormalization conditions ??
how about for the rest of sums [tex]1+2^{m}+3^{m}+...= \zeta (-m) + 1/\epsilon ^{m+1}[/tex]
if i introducte a power regulator [tex]n^{-s}[/tex] in the limit s-->0+ i would get
[tex]\zeta(s-m)=\zeta(-m)[/tex] but i am not sure, why this work
for example in the definition of a functional determinant (in differential geommetry )
[tex]\prod_{i} \lambda_{i}[/tex] apparently there is no divergent term proportional to [tex]log(\epsilon)[/tex] as one would expect since the product is divergent