A question about linear transformations

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Discussion Overview

The discussion revolves around the properties of linear transformations when expressed in different bases, specifically whether the domain and range of a linear transformation T:W -> W remain the same when represented as [T]_B with respect to a different basis B. The scope includes theoretical considerations of linear algebra and the implications of changing bases on the representation of transformations.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant asserts that the domain and range of the linear transformation will remain the same when expressed in a different basis.
  • Another participant agrees with this intrinsic perspective but introduces a different viewpoint, suggesting that a basis can be seen as an isomorphism from the vector space to a coordinate space, leading to a representation where the domain and range of [T]_B are R^n rather than V.
  • This participant further explains that the composition involving the isomorphism and the transformation leads to a conclusion that challenges the initial assertion about the domain and range remaining as V.
  • A later reply expresses confusion regarding the implications of the previous statements, questioning whether it would be incorrect to state that [T]_B: V -> V.

Areas of Agreement / Disagreement

Participants express differing views on whether the domain and range of [T]_B can be considered as V or if they should be viewed as R^n, indicating that multiple competing perspectives remain unresolved.

Contextual Notes

The discussion highlights the dependence on definitions of basis and transformations, as well as the implications of viewing transformations in different coordinate systems. There are unresolved nuances regarding the interpretation of domain and range in the context of linear transformations.

Artusartos
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If we have a linear transformation T:W -> W. Then if we write T with respect to a different basis B, will the domain and range still be W? So, will we have [itex][T]_B : W \rightarrow W[/itex] ?

If not, can anybody explain to me why?

Thanks in advance.
 
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Yes, the domain and range will remain the same.
 
micromass is of course quite right in an intrinsic sense. nothing auxiliary changes the domain and range of a map.

still i look at these things a little differently. to me a basis is an isomorphism from the given vector space V to a coordinate space R^n.

then the matrix associated to that basis is a map from coordinate space to itself.

i.e. if T:V-->V, and the basis B defines the isom B:V-->R^n,

then we have [T]B:R^n-->R^n, where the composition

B^-1o[T]BoB: V-->R^n-->R^n-->V equals T:V-->V.

Thus in this sense, the domain of [T]B is R^n not V, and the range of [T]B is the image of the range of T under the isomorphism B:V-->R^n.
 
Last edited:
mathwonk said:
micromass is of course quite right in an intrinsic sense. nothing auxiliary changes the domain and range of a map.

still i look at these things a little differently. to me a basis is an isomorphism from the given vector space V to a coordinate space R^n.

then the matrix associated to that basis is a map from coordinate space to itself.

i.e. if T:V-->V, and the basis B defines the isom B:V-->R^n,

then we have [T]B:R^n-->R^n, where the composition

B^-1o[T]BoB: V-->R^n-->R^n-->V equals T:V-->V.

Thus in this sense, the domain of [T]B is R^n not V, and the range of [T]B is the image of the range of T under the isomorphism B:V-->R^n.

I'm not sure if I understand this...You say that micromass's answer would be considered right, but then you say "domain of [T]B is R^n not V, and the range of [T]B is the image of the range of T under the isomorphism B:V-->R^n." So would it be wrong to say [itex][T]_B : V \rightarrow V[/itex]?
 

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