A question from Real and Complex Analysis (Rudin's).

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The discussion focuses on understanding theorem 1.17 from Rudin's Real and Complex Analysis, specifically how to demonstrate that the function sequence \phi_n(t) is monotonic increasing. It suggests using the function k_n(t) = floor(2^n t) and the property that floor(2x)/2 is greater than or equal to floor(x). The approach involves analyzing the function for different intervals of t: [0, n), [n, n+1), and [n+1, ∞). The user concludes that checking the case for t in [0, n) suffices, as the other cases are trivial. This highlights the importance of interval analysis in proving monotonicity in function sequences.
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I am trying to understand theorem 1.17 in page 15-16 international edition 1987.
How do you show that \phi_n(t) is a monotonic increasing sequence of functions?
 
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It might be easier if you note that

k_n(t)=\text{floor}(2^nt)

and \text{floor}(2x)/2\ge \text{floor}(x).

Then, when you want to show that \varphi_n(t)\le\varphi_{n+1}(t) consider the cases where 0\le t<n, n\le t<n+1 and n+1\le t separately.
 
Thanks, got it, basically I only need to check for t in [0,n) the other case is trivial.
 

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