A rocket moves upward, starting from rest.

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SUMMARY

A rocket accelerates upward from rest at 32.2 m/s² for 5.84 seconds before running out of fuel. The final velocity at the end of this period can be calculated using the formula v = a * t, resulting in a velocity of 188.488 m/s. After fuel depletion, the rocket continues to ascend until it reaches its peak height, which can be determined using the equation h = v² / (2g), where g is the acceleration due to gravity (9.81 m/s²). The total height reached by the rocket above the ground is approximately 188.488 m.

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Homework Statement



A rocket moves upward, starting from rest with an acceleration of 32.2 m/s2 for 5.84 s. It runs out of fuel at the end of the 5.84 s but does not stop. How high does it rise above the ground?


Homework Equations



I do not know. All equations I have tried have been missing a variable.

The Attempt at a Solution



I tried finding the velocity and then adding it to what I got when plugging it into xf=xi+vi x t + 1/2g x t^2
 
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chewy96 said:

Homework Statement



A rocket moves upward, starting from rest with an acceleration of 32.2 m/s2 for 5.84 s. It runs out of fuel at the end of the 5.84 s but does not stop. How high does it rise above the ground?


Homework Equations



I do not know. All equations I have tried have been missing a variable.

The Attempt at a Solution



I tried finding the velocity and then adding it to what I got when plugging it into xf=xi+vi x t + 1/2g x t^2

Break the motion of the rocket into two parts. Yes, you need to find the velocity the rocket is at after 5.84 seconds. Then you can use this information in the second stage of its motion.

Show your calculations, so we can see what you are getting.
 

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