The problem involves a runner's weight, with a specific focus on the percentage of that weight attributed to water. Participants are tasked with calculating the number of moles of water in the runner's body and the total number of water molecules present.
The discussion is ongoing, with participants providing feedback on each other's calculations and questioning assumptions about the units used. Some guidance has been offered regarding the need for unit consistency, and there is recognition of the confusion surrounding the mass calculation.
There is a noted confusion regarding the conversion of weight to mass, particularly in the context of using different units (grams vs. kilograms). Participants are also addressing the implications of their calculations based on these unit considerations.
His mass is only 70.1 grams?! Check your units.Alice7979 said:70.1 g
What happened to the E23?Alice7979 said:6.022E23 * 2.765 = 1.665
Is this reasonable? A man who weighs 70.1 grams? Must be a world record...Alice7979 said:The Attempt at a Solution
a)
687/9.8=70.1 g
70.1 * .71 = 49.77 g of h20
49.77/18 u = 2.765
So does that change your answer?Alice7979 said:I forgot the formula was in kg
Yes it did, thanksharuspex said:So does that change your answer?
Always happy to have corroboration.Nathanael said:(Posted at the same time as haruspex, oops)