A Series of Even numbers squared

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A general formula for the sum of the squares of even numbers, such as 2^2 + 4^2 + 6^2 + ... + N^2, can be derived by factoring out 2^2 from the series. This simplifies the series to 1^2 + 2^2 + 3^2 + ... + (N/2)^2, allowing the use of the known formula for the sum of squares. The sum of squares formula is given by 1/6 * n(n+1)(2n+1), where n is the number of terms. By applying this formula to the adjusted series, one can find the sum of the original series of even numbers squared. The discussion highlights the importance of recognizing common factors to simplify complex series.
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Homework Statement



Is there a general formula for the sum of such a series (or can it be self derived) ?

2^2 + 4^2 + 6^2 + 8^2 ... N^2 (all the way till some even number N)

Homework Equations



\sum r^2 (from r=1 to r=N) = 1/6 * n(n+1)(2n+1)

The Attempt at a Solution



No clue where to start.
 
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Do all the terms have a common factor that you can pull out?
 
Oh... I did not see that. Great thinking !

After taking 2^2 common we will get a simple sequence :

1^2 + 2^2 + 3^2 + 4^2 ...

I think I get it !
 

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