- #1

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## Homework Statement

Solve for A

27 = 81/√3a-3

## Homework Equations

## The Attempt at a Solution

Im not sure where to begin with this question. Can someone go through all the steps into solving for A. Thanks

- Thread starter eXmag
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- #1

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Solve for A

27 = 81/√3a-3

Im not sure where to begin with this question. Can someone go through all the steps into solving for A. Thanks

- #2

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Whatever value of "a" is in the denominator, it has to be moved to the numerator, usually by multiplying both sides of the equation by the appropriate term containing "a". If it's sqrt(3a - 3) then multiply both sides of the equation by sqrt (3a - 3) to get:

27 * sqrt(3a - 3) = 81.

Then continue to solve for "a".

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Edit:never mind someone else answered it first

- #4

SammyS

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Begin by using enough sets of parentheses to make the problem unambiguous.## Homework Statement

Solve for A

27 = 81/√3a-3

## Homework Equations

## The Attempt at a Solution

I'm not sure where to begin with this question. Can someone go through all the steps into solving for A. Thanks

Is it

[itex]\displaystyle 27=\frac{81}{\sqrt{3a-3\,}}[/itex]

or

[itex]\displaystyle 27=\frac{81}{\sqrt{3a\,}-3}[/itex]

or

[itex]\displaystyle 27=\frac{81}{\sqrt{3\,}\,a-3}[/itex]

or

[itex]\displaystyle 27=\frac{81}{\sqrt{3a\,}}-3[/itex]

or what it means literally with there being no parentheses

[itex]\displaystyle 27=\frac{81}{\sqrt{3\,}}a-3[/itex]

?

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- #6

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^the first example you gave sammy, how would I go through the steps to solve for A?

- #7

SammyS

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Isolate the radical.

Square both sides.

Square both sides.

- #8

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Ok, sorry Im not really math literate. How would you isolate the radical?

- #9

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27 x √3a-3 = 81

√3a-3 = 81/27

√3a-3 = 3

3a-3 = 9

3a = 9 + 3

3a = 12

a = 12/3

a = 4

- #10

SammyS

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Now, check your answer by plugging into the original problem.

27 x √3a-3 = 81

√3a-3 = 81/27

√3a-3 = 3

3a-3 = 9

3a = 9 + 3

3a = 12

a = 12/3

a = 4

- #11

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perfect...thank you very much sammy!

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