Absolute value in separable ODEs?

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SUMMARY

The discussion centers on solving the variable separable ordinary differential equation (ODE) given by \(\frac{dy}{dx} = 3y\). The solution is derived as \(y = Ae^{3x}\), where \(A\) is a constant. The integration process leads to \(\ln |y| = 3x + C\), resulting in \(|y| = Ae^{3x}\). The clarification provided indicates that while \(A = e^C\) is positive, the absolute value is necessary to account for both positive and negative solutions, leading to \(y = Ae^{3x}\) or \(y = -Ae^{3x}\).

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perishingtardi
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Suppose I have a variable separable ODE, e.g.,
\frac{dy}{dx} = 3y.
We all know that the solution is y=Ae^{3x} where A is a constant. My question is as follows. To actually find this solution we rearrange the equation and integrate to get
\int \frac{dy}{y} = 3 \int dx,
which gives
\ln |y| = 3x + C where C is a constant. I would have thought that this gives the solution
|y| = Ae^{3x} \qquad \mbox{where} \qquad A=e^C.
My question is how can we get rid of the absolute value sign in the actual answer? Is it because A = e^C must always be positive? But how come in general that does not have to be true for the ODE to be satisfied?
 
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It is precisely for that reason that you must have the absolute value on y.

Yes, |y|= Ae^x where A= e^C is positive.

Therefore y= Ae^x or y= -Ae^{x}.
 
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