Absolute value on both side of equation

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The discussion revolves around solving an absolute value equation and clarifying the correct solution. The book's answer states that x must be greater than or equal to 0 or equal to -2/3. A mistake in the initial reasoning was identified, specifically the incorrect assumption that the expressions are equal for all real numbers. The correct approach involves breaking the equation into cases based on the absolute value properties, leading to the conclusion that x must be non-negative or specifically equal to -2/3 when the expression inside the absolute value equals zero. This method is applicable to similar absolute value equations.
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I solved this absolute value equation and I am confuse about the answer given in the book for this question, the answer in the book is x > = 0 or x = -2/3 please tell me how can I get this answer from the following solution. Please tell the method which should be true for all such type of questions.
look at the image below
[PLAIN]http://img261.imageshack.us/img261/1577/imgsb.jpg
 
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ok well... one of the mistakes I see is how you reached the conclusion "3x +2 =3x +2 for all real nobs"

well, this isn't true... is it? ex: x= -1. |3(-1)+2(-1)| does not equal (-1)|3(-1)+2|.

Break it up like this:
{|3x^2 + 2x|= |x||3x+2| = x |3x + 2| } \Rightarrow { |x|=x , for (3x+2) \neq 0 }

Hence, this is true for all x \geq 0.

Now, separately consider the case (3x+2)=0. What do you get? x= -2/3

Note: LaTeX is being crazy!
 
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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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