Absolute Value with two expressions.

Click For Summary

Discussion Overview

The discussion revolves around solving an absolute value equation represented as a piecewise function. Participants explore methods for finding solutions and sketching the graph of the function within specified intervals.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant expresses difficulty in finding valid x values that satisfy the equation when substituted back.
  • Another participant suggests representing the expression as a piecewise function and asks for further steps to be taken.
  • One participant claims to have found a solution at x=1 and seeks guidance on sketching the area between -1 and 2.
  • A later reply indicates that there should be two valid roots and advises checking each piece of the function for roots within their respective domains.
  • The same reply provides specific function values at the endpoints of the middle piece and suggests plotting these points to sketch the graph.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the number of valid roots, as one participant states there is only one solution while another suggests there are two. The discussion remains unresolved regarding the complete solution set.

Contextual Notes

There are limitations related to the assumptions made about the roots and the specific domains of the piecewise function. The discussion does not clarify all mathematical steps involved in determining the roots.

stuart4512
Messages
3
Reaction score
0
How do I do this? I have tried a few methods and end up getting x values that don't work when placed back into the equation.

View attachment 3670
 

Attachments

  • Untitled.png
    Untitled.png
    3.4 KB · Views: 98
Mathematics news on Phys.org
I would write the expression as a piecewise function:

$$f(x)=\begin{cases}-3x-5, & x<-1 \\[3pt] x-1, & -1\le x\le2 \\[3pt] 3x-5, & 2<x \\ \end{cases}$$

Can you proceed?

edit: I have moved this thread here from our Linear Algebra subforum, as this is a better fit. :D
 
I got the only solution to be at x=1.
How do I sketch the area between -1 and 2?
 
stuart4512 said:
I got the only solution to be at x=1.
How do I sketch the area between -1 and 2?

You should find 2 valid roots. Check the root of each piece, and if it is in the given domain for that piece, then it is a valid root.

As for the middle piece, just compute the end points, and connect them with a line segment.

$$f(-1)=-2$$

$$f(2)=1$$

So, plot the points $(-1,-2),\,(2,1)$ and connect them.
 

Similar threads

Replies
1
Views
1K
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K