EXPERIMENT ABSORPTION OF γ - RADIATION IN LEAD AND CALCULATION OF ABSORPTION COEFFICIENT µ Using equation (3) / slope of graph lnC vs d - estimate µ. This should be in units of per meter (m-1 ). The formula in the analysis are as follows : 1. I = I0 e-μd 2. C(d) = C0 e-μd 3. lnC = lnC0 -μd You may ignore the decimal point at the RANGE=10 setting on the scaler/timer ! so the count then turns out to be whole numbers . Data (where d is the thickness of the lead sheets): d(m) = 0.0121 ,0.0063 ,0.0025 ,0.0184 ,0.0146 ,0.008 Count/min = 636 ,1050 ,1474 ,424 ,454 ,700 C (counts/min) - background count = 28 Find ln C For the graph i subbed in the values of C to lnC and plotted it vs d(m) ,the result i got as for the line eq. was y = -0.0116x +0.0886 in excell with the tread line . I hope the axis were right :P . So μ≈ -0.0116 Using the equation was hard for me as i'm not sure which component is which , i feel like what im doing is awfully wrong. I tried to work out μ by subbing in values from the table to C(d) and C0 equation 2 i did the same for the 3 equation and tried to solve with rules of logs , taking C0 as background count of 28 . I would appreciate any explanation so i can do the calculation and see what happens .