Are H Union K and Z(g) Subgroups in Group Theory?

Click For Summary
SUMMARY

The discussion focuses on two problems in group theory related to subgroups. The first problem establishes that the union of two subgroups, H and K, denoted as H ∪ K, is closed under inverses, confirming that if x belongs to H or K, then x-1 also belongs to H or K. The second problem involves proving that the centralizer Z(g) of an element g in a group G is a subgroup of G. The proof demonstrates that Z(g) is non-empty, closed under multiplication, and contains inverses, thus confirming Z(g) as a subgroup.

PREREQUISITES
  • Understanding of group theory concepts, particularly subgroups.
  • Familiarity with the definitions of union and inverses in the context of groups.
  • Knowledge of the centralizer concept in group theory.
  • Ability to perform algebraic manipulations involving group elements.
NEXT STEPS
  • Study the properties of subgroup unions in group theory.
  • Learn about the centralizer and its applications in group theory.
  • Research the concept of normal subgroups and their significance.
  • Explore examples of groups and their subgroups to solidify understanding.
USEFUL FOR

Students and researchers in abstract algebra, particularly those focusing on group theory, as well as educators seeking to clarify subgroup properties and centralizers.

jbarrera
Messages
3
Reaction score
0
Abstract Algebra Questions...

I have two problems that I'm a little puzzled by, hopefully someone can shed some light.

1) Show that if H and K are subgroups of the group G, then H U K is closed under inverses.

2) Let G be a group, and let g ε G. Define the centralizer, Z(g) of g in G to be the subset
Z(g) = {x ε G | xg = gx}.
Prove that Z(g) is a subgroup of G.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
For problem 2 this is what I have but I am not sure if it is correct.

Since eg = ge for g in G, we know Z(g) is not the empty set.

-Take a in Z(g) and b in Z(g), and take any g in G, then we have...
(ab)g = a(bg) = a(gb) = (ag)b = (ga)b = g(ab). Thus ab is in Z(g).

- Take a in Z(g) and g in G. Then we know...
ag = ga
(a^-1* a )g = (a^-1 * g) a (multiplying both sides by a inverse)
e * g = a^-1 * g*a
g * a^-1 = a^-1 * g * (a * a^-1) ( multiplying again by a invese)
g * a^-1 = a^-1 * g

Thus a^-1 is in Z(g), so Z(g) is a subgroup of G.
 
Physics news on Phys.org


what you did on 2 is fine. you could have saved a little time by showing b-1 is in Z(g) whenever b is, and then showing ab-1 is in Z(g) when a and b are, but not much.

for 1) x in HUK means:

x is in H...or
x is in K..or both.

so start by assuming x is in H, what can you say about x-1?

next, if x is not in H, it must be in K, and use a similar agument.
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

Similar threads

  • · Replies 1 ·
Replies
1
Views
573
  • · Replies 26 ·
Replies
26
Views
895
  • · Replies 3 ·
Replies
3
Views
922
  • · Replies 13 ·
Replies
13
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K