Acceleration of a 1kg Mass Under a 100N Force

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Homework Help Overview

The discussion revolves around the acceleration of a 1kg mass when subjected to a 100N force, exploring the implications of Newton's second law of motion, F=ma. Participants are questioning the straightforward application of this principle in various contexts, particularly in relation to buoyancy and terminal velocity.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the basic application of F=ma, with some questioning its sufficiency in more complex scenarios like buoyancy. Others suggest looking into alternative approaches, such as Stokes' Equations, to address the nuances of forces acting on objects in fluid environments.

Discussion Status

The conversation is ongoing, with participants exploring different interpretations of the fundamental principles involved. Some guidance has been offered regarding the complexities of applying F=ma in specific situations, but no consensus has been reached.

Contextual Notes

There is mention of potential misunderstandings related to the application of F=ma in buoyancy contexts, indicating that assumptions about straightforward calculations may need to be revisited. Additionally, references to external resources like Stokes' Equations suggest that further exploration of the topic is warranted.

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obvious question, but what happens when a 100N force acts on a mass of 1kg. What is the acceleration? is it 100 meters per second squared?
 
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Obvious answer. F=ma.
 
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see "followup to easy question"
 
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I was looking online and i finally found where everything goes wrong.. With buoyancy, you cannot use simply F=ma to calculate acceleration of a bubble. It is not that simple. it ends up giving nearly unlimited acceleration in many circumstances when trying to apply it. ill get back about it when i have timelooren try not to be so cocky next time. everything is not always as straightforward as it may seem
 
Sorry.

I still maintain that F=ma. In your other thread, one post suggests "Check out Stokes' Equations on the terminal velocity of falling spheres." This seems the best approach. There, simply put, F=bv, where b is a damping constant. I believe that the velocity dependence arises not directly from a fundamental law but from nonconservative (e. g., frictional) action by forces on the atomic level.
 

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