Acceleration Vector Word Problem

In summary, the famous quarterback Fleet O. Floote is attempting a quarterback draw at 4.6 m/s towards his goal line. Upon impact with a linebacker, their combined final velocity is 3.8 m/s at an angle of +120° from the original direction. The time it took to change direction at impact was 0.20s. Using the appropriate horizontal coordinate system, the average acceleration vector of the quarterback during the tackle can be calculated. However, it seems that the given angle of +120° may be incorrect and could be meant to be 30° instead.
  • #1
Retweetfire
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0

Homework Statement


Famous quarterback Fleet O. Floote is attempting a quarterback draw by running up the middle toward his goal line at 4.6 m/s. A linebacker hits him squarely, and their combined final velocity is 3.8 m/s at an angle of +120.° from the quarterback's original direction. The time it took to change direction at impact was 0.20s. Choose an appropiate horizontal coordinate system and calculate the average acceleration vector of the quarterback during the tackle.

Homework Equations


a = ΔvΔt
329864.image3.png


The Attempt at a Solution


v1 = 4.6 m/s 90.0°
v2 = 3.7 m/s 120.°

v1x = 0 m/s
v1y = 4.6 m/s

v2x = 3.7 cos 60° = 1.9 m/s
v2y = 3.7 sin 60° = 3.2 m/s

I have this, but I feel that I'm missing something.
 
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  • #2
Please draw a diagram, and show it to us. Thank you.

It seems to me, if the new velocity direction is 120 degrees to the original direction, one of the new components has to be negative.
 
  • #3
Hello rf, :welcome:
Retweetfire said:
at an angle of +120.° from the quarterback's original direction
Can you post a sketch and compare with what you (were going to) calculate ? Then complete your attempt ?
 
  • #4
BvU said:
Hello rf, :welcome:

Can you post a sketch and compare with what you (were going to) calculate ? Then complete your attempt ?
 

Attachments

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  • #5
That's only at a 30 degree angle to the QBs original velocity. Did they really mean 120 degrees, or did they really mean 30 degrees?
 
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