Acid and Base Questions: Bronsted-Lowry Acids and Bases"

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SUMMARY

The discussion centers on Bronsted-Lowry acids and bases, specifically identifying which species do not act as both. The consensus is that OH- is a strong base but does not function as an acid. Participants also explore unfavorable equilibria in reactions involving strong acids and bases, noting that strong acids like HI and NaOH lead to one-directional reactions. Additionally, the concept of the leveling effect of solvents is introduced, emphasizing the importance of solvent choice in comparing acid strengths.

PREREQUISITES
  • Understanding of Bronsted-Lowry acid-base theory
  • Knowledge of strong acids and bases, including NaOH and HI
  • Familiarity with chemical equilibria and reaction directionality
  • Concept of solvent leveling effect in acid-base chemistry
NEXT STEPS
  • Study the properties and reactions of Bronsted-Lowry acids and bases
  • Research the leveling effect of solvents in acid-base reactions
  • Examine the concept of equilibrium constants in chemical reactions
  • Learn about strong bases such as CH3Li and their reactivity
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Chemistry students, educators, and professionals interested in acid-base theory, reaction mechanisms, and solvent effects in chemical equilibria.

himura137
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1)Which of the following is not both a Bronsted-Lowry acid and a Bronsted-Lowry base?

a. OH-

b. HSO4-

c. SH-

d. HCO3-

e. H2PO4-

I knwo its not HCO3, H2PO4- AND HSO4-, but i cannot figure out whether OH can act as an acid and base or not, i know its produced when a base react with water, but not sure if itself can be reacted as a acid and base since if it does, OH would become O2 or H2O, not sure if that's possible.

2)
Which reaction of these potential acids and bases does not occur to any appreciable degree due to an unfavorable equilibrium?



a. NaC2H3O2 (aq) + HI

b. NaNH2 in liq. NH3 + ethanol

c. CH3Li in hexane + ethyne

d. NaOH (aq) + CH3CH2CH2CO2H

e. CH3CH2ONa in ethanol + ethene

For it to have an unfavorable equilibrium, one of the reactant would have to be a strong acid or base, since HI, NH3, NaOH are strong acid or base, they would form unfavorable equiibrium as the reaction would only go one way, i am unsure whether whether the chemicals in C and E are strong acid or bases.



3) Comparison of the acidity of strong acids in solution requires the use of a solvent less basic than water

this would be false because something that is less basic than water would make it an acid, and you can't compare strong acid with weak acid in the same solution, which mean that statement is false. Am i right?


Please help, thank you
 
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himura137 said:
1)Which of the following is not both a Bronsted-Lowry acid and a Bronsted-Lowry base?

a. OH-

b. HSO4-

c. SH-

d. HCO3-

e. H2PO4-

I knwo its not HCO3, H2PO4- AND HSO4-, but i cannot figure out whether OH can act as an acid and base or not, i know its produced when a base react with water, but not sure if itself can be reacted as a acid and base since if it does, OH would become O2 or H2O, not sure if that's possible.

2)
Which reaction of these potential acids and bases does not occur to any appreciable degree due to an unfavorable equilibrium?



a. NaC2H3O2 (aq) + HI

b. NaNH2 in liq. NH3 + ethanol

c. CH3Li in hexane + ethyne

d. NaOH (aq) + CH3CH2CH2CO2H

e. CH3CH2ONa in ethanol + ethene

For it to have an unfavorable equilibrium, one of the reactant would have to be a strong acid or base, since HI, NH3, NaOH are strong acid or base, they would form unfavorable equiibrium as the reaction would only go one way, i am unsure whether whether the chemicals in C and E are strong acid or bases.



3) Comparison of the acidity of strong acids in solution requires the use of a solvent less basic than water

this would be false because something that is less basic than water would make it an acid, and you can't compare strong acid with weak acid in the same solution, which mean that statement is false. Am i right?


Please help, thank you

1) OH- is a strong base e.g. NaOH

2)CH3Li is a strong base

3)Have you heard of the "leveling effect of a solvent?" You want to pertain to the competitiveness of the strong acids. Would a more basic solvent address this issue by reacting more violently with both of the acids? The direction you go should pertain to a setting where one of the strong acids now has an significant equilibrium constant in that solvent, which is more or less higher then the other, previously strong, acid.
 

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