Action corresponding to photon emission

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SUMMARY

The discussion focuses on determining the action corresponding to photon emission during an electron transition within Feynman's path integral formulation. Participants clarify that the first-order diagram involves an incoming electron with momentum p and an outgoing electron with momentum (p-k), alongside a photon with momentum k. The action S related to this process does not exist as a standalone entity; instead, it arises from the perturbation expansion of the classical action, primarily through the minimal coupling term (##j_{\mu} A^{\mu}##) that links the electron field to the Maxwell field.

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  • Understanding of Feynman's path integral formulation
  • Knowledge of quantum electrodynamics (QED)
  • Familiarity with perturbation theory in quantum mechanics
  • Basic concepts of Lagrangian mechanics and action principles
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  • Study the minimal coupling term in quantum electrodynamics
  • Explore perturbation theory applications in QED
  • Investigate the role of Feynman diagrams in particle interactions
  • Learn about the classical action and its derivation in field theory
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Physicists, particularly those specializing in quantum mechanics and quantum field theory, as well as students seeking to deepen their understanding of photon emission processes and Feynman's path integral approach.

semc
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Hi I am trying to write the probability of photon emission due to transition of electron in feynman's path integral formulation. I am stuck trying to figure out the action corresponding to the photon emission. Would anyone shed some light on this? Thanks
 
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semc said:
Hi I am trying to write the probability of photon emission due to transition of electron in feynman's path integral formulation. I am stuck trying to figure out the action corresponding to the photon emission. Would anyone shed some light on this? Thanks

If I'm not mistaken (and I could very well be, as I'm a dilettante dabbler), the corresponding 1st-order diagram would be an incoming electron with momentum p, and an outgoing electron with a momentum (p-k) and photon with momentum k, so the perturbation expansion term would have a destruction operator for the electron with momentum p, and the electron/photon creation operators with momenta (p-k)/k.

However, if you're asking about the actual action S corresponding to that situation, as in the integral over a term in the Lagrangian, I don't think there is one; the "electron emitting a photon" and all of the other possibilities come from the perturbation expansion of the (exponential of?) the normal, (semi-)classical action, where the only term giving the interaction between the electron field and the Maxwell field is just the minimal-coupling term (##j_{\mu} A^{\mu}##?); everything else derives from that.

But, again, caveat emptor.
 

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