1. The problem statement, all variables and given/known data Add the following 3 displacement vectors and give the answer in ijk notation and in magnitude and direction format. A = 3i - 3j m B = i - 4j m C = -2i + 5j m. Then I have to do a scetch of the resultant vector...which i'll call D. 2. Relevant equations 3. The attempt at a solution So I know to get vector D's i hat and j hat components...i just add the i's and j's of the vectors that make it up so i = 3 + 1 - 2 = 2 j = -3 - 4 + 5 = -2 right? so then to find the magnitude of D i do √(2)² + (-2)² which comes out to √8 which is roughly 2.83 m here Then to find the angle i do the inverse tan of (-2/2) or -1....which comes out to -45° Now to graph....should I find the magnitude and angle of each vector? A = √(3)² + (-3)² = √18 = 4.24 m at -45° B = √(1)² + (-4)² = √17 = 4.12 m at -76° C= √(-2)² + (5)² = √29 = 5.39 m at -68° Do I graph them just like this? Because how can the resultant vector be at the SAME angle at vector A? It would be a smaller version of vector A because the magnitude of A is >D and the angle is the same. Can anyone point out where I'm misunderstanding this?