When we derive the phase difference in the classical experiment of the solenoid as shown below(adsbygoogle = window.adsbygoogle || []).push({});

http://www.public.asu.edu/~ziyads/Aharonovbohm.pdf [Broken]

Now what if we change the path from the sorce to screen so it follows a rectangular path like this

http://www.public.asu.edu/~ziyads/rect.gif [Broken]

the phase difference i.e equation 10 in the slides above will remain the same cause no matter what the path the the closed loop integral of the curl of A remains the same.

NOw what if I change it a bit, and apply a parpendicular magnetic field throughout the region and my gauge is A=(-By/2, Bx/2,0)

How will the phase differnce change of the rectangular path.

and what about if A=(By,0,0) which should be the same as that of A=(-By/2, Bx/2,0)

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# Aharonov Bohm effect

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