Hi!! Q: A column of air length 36cm is closed at both ends, resonates to as sound of third lowest frequceny of 1445Hz. Calculate the air temperature given that the reasonable temperature falls between 10 and 20 C?? Here is what I tried: Given T= 20 ( 30-10= 20) Required: vs & T Analysis: vs= 332m/s+T(0.60m/s C) & T= vs-332/0.60 Solution: vs= 332m/s+(20C)(0.60 C) = 332m/s+12m/s = 344m/s now we the speed, & we can find the temperature: =344m/s-332m/s/0.60m/s C = 12/0.60 = 20 So the air temperature is 20 C. I would really appericate if sum1 could help. Thanks alot.