Algebra: distance from a fixed point

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Homework Help Overview

The discussion revolves around an algebra problem related to calculating distance from a fixed point, specifically involving directional components and algebraic expressions.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to establish a coordinate system for the problem and expresses confusion regarding the discrepancy between their calculated answer and the book's answer. Other participants question the accuracy of the book's response and suggest it may contain a typo.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and questioning the validity of the provided answer. Some guidance has been offered regarding potential errors in the book.

Contextual Notes

There is mention of a fixed point O and directional assumptions (North as positive), but the exact details of the problem setup are not fully disclosed. The original poster's calculations and the book's answer are in conflict, leading to speculation about possible typographical errors.

drooble122
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Homework Statement
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Relevant Equations
Basic algebra
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The first image is the question and the second is the answer.
My thinking is let's say North is positive, and South is negative. Fixed point O is the starting point. Then the question becomes +(2a-b)-(3a+2b). The answer should be -a-3b. I cannot fathom why the book gives the answer as a+b. Any help would be appreciated. Thank you.
 
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I'd say you were correct. What book are you using?
 
It's probably a typo and they meant to say 2a+b miles north.
 
Office_Shredder said:
It's probably a typo and they meant to say 2a+b miles north.
Exactly.
 

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