Undergrad Algebra equation with variable as exponent

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SUMMARY

The discussion focuses on solving for the interest rate "r" in the context of mortgage payments using algebraic methods and numerical techniques. The equation V/T = r(1-r^n)/(1-r) is analyzed, with participants suggesting Newton's method as a viable computational approach. Additionally, the Excel RATE function is highlighted as a practical tool for calculating the interest rate per period of an annuity, which iteratively approaches a solution. The conversation also critiques the original formula presented for calculating discount factors.

PREREQUISITES
  • Understanding of algebraic equations and variables
  • Familiarity with Newton's method for numerical approximation
  • Knowledge of Excel functions, specifically the RATE function
  • Basic concepts of present value (PV) and annuities
NEXT STEPS
  • Research the implementation of Newton's method in Excel spreadsheets
  • Learn about the Excel RATE function and its applications in financial calculations
  • Explore algebraic methods for solving equations with variables as exponents
  • Study the concept of discount factors and their calculations in finance
USEFUL FOR

Mathematicians, financial analysts, and anyone involved in mortgage calculations or interested in numerical methods for solving equations.

adamaero
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This equation takes a present value (PV) to find mortgage payments, PMT:
1665697695309.png


Alternatively, switching V for PV and T for PMT:
V/T = r(1-r^n)/(1-r)

What is an algebraic method to solve for "r"?
Can it not be solved for? I realize I can just find out "r" by trial by error in Excel using the PMT function.

Although, I would like to find a way to just solve for "r" outright. Thanks.
 
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Last edited:
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anuttarasammyak said:
As text says computtion by Newton's method https://en.wikipedia.org/wiki/Newton's_method seems applicable.

It is just a random picture. Newton's method can be punched into an excel spreadsheet?

How?
 
adamaero said:
Alternatively, switching V for PV and T for PMT:
V/T = r(1-r^n)/(1-r)
Let me write it in order to use ordinary x-y graph picture
y=f(x)=\frac{x(1-x^n)}{1-x}-a
where n is not a variable but a given number and
a=\frac{PV}{PMT}
is also a given number. The problem is to find x where y=0.

The prescription of Newton method :

Preparation
1 . Get formula of derivative f'(x)
2 . Get formula of tangential line at (x,y=f(x)) with 1.
3 . Get formula of x where the tangential line cross with x-axis with 2, say g(x).

Then
Let x=##x_0## which you assume to be approximate solution
Get value of ##x_1=g(x_0)##
Get value of ##x_2=g(x_1)##
Get value of ##x_3=g(x_2)##
----

Repeat it until you find ##x_n## seem to remain unchanged in PC calcualtion that means ##f(x_n)## is enough close to zero in your calculation environment.
 
Last edited:
I suspect that you are looking for the Excel RATE function, which is described as follows:
Description

Returns the interest rate per period of an annuity. RATE is calculated by iteration and can have zero or more solutions. If the successive results of RATE do not converge to within 0.0000001 after 20 iterations, RATE returns the #NUM! error value.

Syntax

RATE(nper, pmt, pv, [fv], [type], [guess])
 
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pasmith said:
I suspect that you are looking for the Excel RATE function, which is described as follows:

Thank you!
 
THe formula in the OP does not look right. for n=1 and r=.05 it gives a discount factor of (.05)(.95)/.95 = .05 the correct factor is (1+r)-1=.95

The discount factor of a payment in perpetuity is simply

r-1

A finite series of payments is simply the sum of each payment's PV, so the PV of a stream of $1 payments is

Σ(1+r)-n with n going from first to last payment
 
you can also get rid of the exponents by switching to log returns and continuous compounding

so
(1+r)-n = exp[-rn] where r = log(1+r)
 

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