Algebra Question: Solving for Reaction Constant with Coefficient and Factor

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Discussion Overview

The discussion revolves around solving for an overall reaction constant in a chemical equation, specifically focusing on the mathematical manipulation of expressions related to reaction kinetics. Participants explore the algebraic steps needed to transform one equation into another, examining the relationships between coefficients and factors in the context of the problem.

Discussion Character

  • Mathematical reasoning
  • Technical explanation
  • Exploratory

Main Points Raised

  • One participant presents a mathematical expression involving a reaction constant and seeks help in transforming it into a different form.
  • Another participant suggests working backwards from the desired equation to understand the transformation process.
  • A participant proposes a specific algebraic manipulation involving the division algorithm to simplify the expression.
  • Further discussion includes alternative methods for rewriting the expression, emphasizing the importance of understanding the underlying algebraic principles.

Areas of Agreement / Disagreement

Participants engage in a collaborative exploration of the mathematical steps without reaching a consensus on a single method or approach. Multiple viewpoints on how to manipulate the equations are presented, indicating that the discussion remains open-ended.

Contextual Notes

The discussion includes various algebraic techniques and assumptions about the relationships between terms, but does not resolve the mathematical steps or clarify the conditions under which each method is applicable.

Who May Find This Useful

This discussion may be useful for individuals interested in chemical kinetics, algebraic manipulation in chemistry, or those seeking to understand the mathematical foundations of reaction constants.

scrappychic
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I am trying to figure out an overall reaction constant, but I am getting stuck on the math behind the problem. I am at this point in the problem:

[Co(H2O)6] = [Co] x (k[H+]/(1+k[H+]))
And I am trying to mathematically get to
[Co(H2O)6] = [Co] x (1-(1/(1+[H+]k)))

When you ignore the chemistry, the equation is the same as:

a = b x (cd/(1+cd))

going to

a = b x (1-(1/(1+cd)))

How do you factor out the cd from the numerator?

Thanks!
 
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It wasn't factored out. (If it was factored out, it would still be there, but outside. :-p)

Try going the other direction: what sort of things can you do to the latter equation?
 
So if I work backwards, the step before 1-(1/(1+cd)) could have possibly been
[(1+cd)/(1+cd)] - (1/(1+cd)). What would have led me to that step or is that not the correct step backwards?
 
Wait a minute! I think a lightbulb just went off...
 
[(1+cd)/(1+cd)] - (1/(1+cd)) This actually reduces back to cd/(1+cd), right? Because the 1-1=0 and cd is the only thing left in the numerator. So what would prompt me to know that I should change cd/(1+cd) into [(1+cd)/(1+cd)] - (1/(1+cd))?
 
Well, whether you should change it is another question entirely.

But to figure out how to change it, you can simply use the division algorithm.

You're dividing cd by (cd + 1)...

How many times does (cd + 1) go into cd? 1 time, with remainder -1.

So, cd/(cd+1) = 1 + (-1)/(cd+1)

(when figuring out how many times, you just look at the "biggest" terms -- in this case, we consider any term involving "cd" to be bigger than any term that is just a number)


Another method is to look at it and think "Hrm, I can probably write that as A + B/(cd+1)", and then try to solve the equation "A + B/(cd+1) = cd/(cd+1)"


A third way is to learn how to do what you just did in the opposite direction!
 
Last edited:
Thanks so much!
 

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