ALmost got it, mathematical induction, writing terms seperatley

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The discussion focuses on proving the equality of two equations using mathematical induction, specifically the equation \(\sum_{i=1}^{k+2} i2^i = \left(\sum_{i=1}^{k+1} i2^i \right) + (k+2)2^{k+2}\). The user expresses difficulty in manipulating the left-hand side to match the right-hand side, which is \((k+1)2^{k+3} + 2\). Key concepts include separating terms in summation and applying the inductive hypothesis effectively. The community provides guidance on structuring the proof and manipulating the equations.

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mr_coffee
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Hello everyone I'm having problems on this last part of mathematical induction. I have to show that the two equations are equal to each other. The book shows a few examples which i will show below. They are writing the kst term separately from the first k terms.

Heres my problem firstly:
Prove by mathematical induction:
http://img219.imageshack.us/img219/1613/lastscancw1.jpg

My Goal is to prove that those 2 equations do infact equal each other, the boxed equations. Once I write the k term separatley then I go on to substitute from the inductive hypotheiss, then do some algebra.Examples of writing the terms separately:
http://img295.imageshack.us/img295/9369/lastscan3cn3.jpg

Under my problem i attempted to mimic what they are doing, is that it or no? Any help would be great on explaining what they are doing here!

:biggrin:
 
Last edited by a moderator:
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it should be

\sum_{i = 1}^{k + 2} i2^i = \left(\sum_{i = 1}^{k+1} i2^i \right) + (k+2)2^{k+2}


As a simple example consider:

\sum_{i=1}^{4}i = 1 + 2 + 3 + 4 = (1 + 2 + 3) + 4 = \left(\sum_{i=1}^{3}i \right) + 4


more generally, if f is a function defined on the integers, and a, b, and c are integers with a \leq b \leq c then,

\begin{align*}<br /> \sum_{i = a}^{c} f(i) &amp;= f(a) + f(a+1) + \ldots + f(b-1) + f(b) + f(b+1) + \ldots + f(c-1) + f(c) \\ <br /> &amp;= \left( f(a) + f(a+1) + \ldots + f(b-1) \right) + \left( f(b) + f(b+1) + \ldots + f(c-1) + f(c) \right) \\<br /> &amp;= \left( \sum_{i = a}^{b-1} f(i) \right) + \left( \sum_{i = b}^{c} f(i) \right) <br /> \end{align*}


in regards to your problem, f is the function
f(k) = k2^k
and a = 1, b = c = k + 2

Your proof up to this point looks great by the way, very nicely written.
 
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Thanks nocturnal, that explanation was very helpful. Sorry about the delayed responce.

I'm now having the following troubles, i can't seem to manipulate the left hand side of the equation to look like the right hand side.

This is my work:

http://img187.imageshack.us/img187/1449/lastscanfj5.jpg I'm suppose to get that to look like right hand side of the equation, (k+1)*2^(k+3) + 2, any help or suggestions would be great! I tried to factor and expand, and they dont' seem to work or maybe i can't see somthing.

THanks!
:biggrin:
 
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