Alternative to Von Neumann bias correction method

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The discussion centers on the limitations of the Von Neumann bias correction method, which is effective only with a stable bias, such as repeatedly tossing the same loaded coin. The original poster seeks alternative methods for correcting an unstable bias, particularly in scenarios involving a diverse set of coins with varying biases. They clarify that their hypothetical scenario involves an infinite number of coins, each biased towards tails, complicating the correction process. The conversation emphasizes the need for a more detailed understanding of the coin population to address bias effectively. The challenge of bias correction in this context remains unresolved, highlighting the complexity of the problem.
tim1608
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Hi

I have discovered that the Von Neumann bias correction method only works when the bias is 100% stable, for example tossing the same loaded coin again and again.

Does anyone know of a bias correction method which can correct an unstable bias? Is this impossible?

Edit: Let's say I have a bucket of coins, each of which is differently loaded but they are all loaded on the tails side. How can the bias be removed if the coins are each tossed one-by-one?
 
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tim1608 said:
if the coins are each tossed one-by-one?

Are you going to label the coins and toss them in order till all are tossed and then toss them again in the same order?
 
Hi Stephen

Thank you for your reply.

No. The hypothetical "bucket" in my original post has an infinite number of coins.
 
To pose an interesting problem, I think you must say more about the population of coins and how they are selected. (For example, you haven't ruled out an infinite population of two-headed coins.)
 
First trick I learned this one a long time ago and have used it to entertain and amuse young kids. Ask your friend to write down a three-digit number without showing it to you. Then ask him or her to rearrange the digits to form a new three-digit number. After that, write whichever is the larger number above the other number, and then subtract the smaller from the larger, making sure that you don't see any of the numbers. Then ask the young "victim" to tell you any two of the digits of the...

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