(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

In an amusement park rocket ride, cars are suspended from L = 4.37-m cables attached to rotating arms at a distance of d = 6.09 m from the axis of rotation. The cables swing out at an angle of θ = 53.9° when the ride is operating. What is the angular speed of rotation?

2. Relevant equations

(mv^2)/r = mg

wr(angular speed) = v

3. The attempt at a solution

Okay, so first I calculated the total radius which was 6.09 m + (sin53.9)(4.37) and got a radius of 9.62 m. Then, since there is no normal force, the tension is equal to mg, thus making mv^2/r = mg. Masses cancel out and I got v^2/r = g I got a velocity of 9.7145 m/s. Using the angular speed equation :wr = v. For angular speed I got 1.01 deg / sec. Computer says this is wrong, what did I do wrong?

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# Homework Help: Amusement Park Ride - Angular Speed

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