An infinite series transformed from Laplace transform

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SUMMARY

The discussion centers on the transformation of the Laplace transform into an infinite series using integration by parts. The resulting series is identified as an infinite series without a specific name, rather than a recognized Laplace transform series. The mathematical expressions provided illustrate the transformation process, including the integral representation and the series expansion involving derivatives of the function f(t).

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SAT999
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hello. I have transformed the Laplace transform into the infinite series by repeatedly using integration by parts.
What is this infinite series? may be Laplace transform series, or only an infinite series without name?

[tex] L(t)= \int_{t}^{\infty}\frac{f(t)}{e^{st}} dt =-0 + <br /> <br /> \frac{1}{e^{st}}\sum_{n=0}^{\infty}\frac{f^{(n)}(t)}{s^{(n+1)}} [/tex]

[tex] <br /> IL(L(t))= \frac{1}{2\Pi i}\int_{\gamma-i\infty}^{\gamma+i\infty}e^{st}L(t) ds=\frac{1}{2\Pi <br /> <br /> i}\oint_{c}e^{st}L(t) ds = \frac{1}{2\Pi i}\sum_{n=0}^{\infty}\oint_{c}\frac{f^{(n)}(t)}{s^{(n+1)}} <br /> <br /> ds[/tex]

[tex] = \frac{1}{2\Pi i}f(t)\oint_{c}\frac{1}{s} ds = \frac{1}{2\Pi i}f(t)\int_{0}^{2\Pi}\frac{is}{s} <br /> <br /> d\Theta = f(t)[/tex]
 
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I'm not quite sure what you have done there, but the answer is: just another infinite series without name.
 

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