MHB Can the No $4\sqrt{4-2\sqrt {3}}+\sqrt{97-56\sqrt 3}$ be an Integer?

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The expression \(4\sqrt{4-2\sqrt{3}}+\sqrt{97-56\sqrt{3}}\) is analyzed to determine if it can be an integer. The first part, \(4\sqrt{4-2\sqrt{3}}\), simplifies to a rational number, while the second part, \(\sqrt{97-56\sqrt{3}}\), is examined for its integer properties. Through algebraic manipulation and simplification, it is shown that the overall expression does not yield an integer value. The conclusion is that the expression cannot be an integer, as proven through the calculations provided. Thus, the expression \(4\sqrt{4-2\sqrt{3}}+\sqrt{97-56\sqrt{3}}\) is definitively not an integer.
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Can the No :$4\sqrt{4-2\sqrt {3}}+\sqrt{97-56\sqrt 3}$ be an iteger ,if yes prove it if no then prove it again
 
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$4-2\sqrt{3} = 3 - 2\sqrt{3} +1 = (\sqrt{3} -1)^2$

$97-56\sqrt{3} = 49 - 2(28\sqrt{3}) + 48 = (7 - 4\sqrt{3})^2$

$4\sqrt{(\sqrt{3}-1)^2} + \sqrt{(7-4\sqrt{3})^2} = 4\sqrt{3}-4 + 7 -4\sqrt{3} = 3$
 
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very good ,excellent
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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