An object starts from rest and travels 14 cm in the fourth second of its motion. Calculate:
a) the acceleration of the object (assumed uniform)
b) the distance travelled by the object after 4.0 s.
c) the distance travelled in the tenth seconf of motion, if the acceleration is the same throughout its motion.
u=0 s=0.14 m t= 1 sec?
The Attempt at a Solution
I really dont get these questions.. the ones that are 'it travels 2 metres in 5th second of motion:S however if it travelled 14 cm in fourth second of motion does that mean the time would just be one second? For question a) could i use s=ut +0.5at^2? Wait scratch that i just tried it and it didn't work.. umm pls help. These type of questions just confuse me altogether. Thankyou very much