Electron Motion in Charged Plate Region: Time, Distance, and Velocity Components

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SUMMARY

The discussion focuses on calculating the motion of an electron traveling between two charged plates. The electron has an initial horizontal velocity of 3.16 × 109 cm/s and experiences a constant downward acceleration of 2.73 × 1017 cm/s2. The time taken to travel a horizontal distance of 2.42 cm is determined to be 7.42 seconds. The discussion also addresses the need to separate the equations for horizontal and vertical motion to accurately solve for the vertical distance and velocity components.

PREREQUISITES
  • Understanding of kinematic equations, specifically s = ut + 0.5at2
  • Knowledge of horizontal and vertical motion separation in physics
  • Familiarity with concepts of acceleration and initial velocity
  • Basic algebra skills for solving quadratic equations
NEXT STEPS
  • Research the derivation and application of kinematic equations in two-dimensional motion
  • Learn how to separate motion into horizontal and vertical components in physics problems
  • Study the effects of electric fields on charged particles, specifically electrons
  • Explore advanced topics in projectile motion and acceleration due to gravity
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of charged particles in electric fields.

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Homework Statement


An electron, with an initial horizontal velocity of magnitude 3.16 × 109 cm/s, travels into the region between two horizontal metal plates that are electrically charged. In that region, it travels a horizontal distance of 2.42 cm and has a constant downward acceleration of magnitude 2.73 × 1017 cm/s2 due to the charged plates. Find (a) the time required by the electron to travel the 2.42 cm and (b) the vertical distance it travels during that time. Also find the magnitudes of the (c) horizontal and (d) vertical velocity components of the electron as it emerges.

Homework Equations


s = ut +0.5at^2

The Attempt at a Solution


s = ut + 0.5at^2
2.42 = 3.16x10^9t +1.365x10^17t^2
t = 7.42

I'm not sure whether what i did was correct and also don't know how to do parts b, c and d.
 
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You have combined the two different directions for some reason into the same equation. Try to separate the equation for the two directions.
 

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