Analysis of 2 body decay kinematics

  • Context: Graduate 
  • Thread starter Thread starter planesinspace
  • Start date Start date
  • Tags Tags
    Body Decay Momentum
Click For Summary
SUMMARY

In two-body decay kinematics, the momenta of the decay products are always equal and opposite in the center of mass (CM) system of the decaying particle. This principle holds true regardless of the masses of the particles involved. The momentum of particle 1 can be expressed using the equation derived from four-momentum considerations, specifically Equation 37.16 from the Particle Data Group's kinematics documentation. The derivation involves understanding the relationship between energy and momentum, as well as applying Lorentz transformations to transition from the CM frame to the lab frame.

PREREQUISITES
  • Understanding of two-body decay processes in particle physics
  • Familiarity with four-momentum concepts
  • Knowledge of Lorentz transformations
  • Basic proficiency in algebra and calculus for deriving equations
NEXT STEPS
  • Study the derivation of Equation 37.16 in the Particle Data Group's kinematics documentation
  • Learn about Lorentz transformations and their applications in particle decay analysis
  • Explore the concepts of energy-momentum relations in special relativity
  • Review the mathematical foundations of momentum conservation in particle physics
USEFUL FOR

Students and researchers in particle physics, physicists analyzing decay processes, and anyone interested in the mathematical foundations of kinematics in high-energy physics.

planesinspace
Messages
21
Reaction score
0
Hi, I am learning about analysing particles decaying and am on this Wikipedia article: http://en.wikipedia.org/wiki/Particle_decay

Under the 'Two body decay' subsection, there is a description of the momentum of particles 1 and 2 from the rest frame of the parent particle.

I have two questions, firstly, it states that the momentum of particle 1 is equal to the momentum of particle 2, is this always the case? If they are of different mass I would have thought the momentums might be different as well.

Secondly, they state the equation for the momentum of particle 1 (or 2) in terms of the masses of all particles involved. I'm assuming they derived this from the equations mentioned in the preceding section about four momentum, but I cannot see how they have got that final result. When I try to dervie the momentum of particle 1 (or 2), using the results from the preceding section, I end up with: p_1 = sqrt[m_parent^2 + m_2^2 - m_1^2 -m_2\ 2m_parent].

Is anyone able to explain where they got that result from?
Any help greatly appreciated
 
Physics news on Phys.org
In two-body decays, the momenta of the two decay products are always equal and opposite in the center of mass (CM) system of the decaying particle:
(pc)2 = E2 - (mc2)2.
Lorentz transformations to the lab system are performed using the transformation in Section 37.1 of

http://pdg.lbl.gov/2002/kinemarpp.pdf

Two-particle dacays are specifically discussed in Section 37.4.1

Bob S
 
Thanks for the link. Equation 37.16 is the one that I was having trouble with, and apologies for my ignorance but I still don't see how they arrived at that formula?

If p= E-m, then how do they arrive at that equation? I'm guessing the square root has something to do with getting the magnitude of the p vector, but where do those two terms in the square root come from?
 
planesinspace said:
Thanks for the link. Equation 37.16 is the one that I was having trouble with, and apologies for my ignorance but I still don't see how they arrived at that formula?

If p= E-m, then how do they arrive at that equation? I'm guessing the square root has something to do with getting the magnitude of the p vector, but where do those two terms in the square root come from?
Look at Equations (14) and (15) in

http://www.google.com/url?sa=t&sour...TC6ZYE&usg=AFQjCNFB_gFuNy0JYBlOZEzYMSSjBvxBwg

Bob S
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K