Analysis of 2 body decay kinematics

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    Body Decay Momentum
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Discussion Overview

The discussion focuses on the kinematics of two-body particle decay, specifically addressing the momentum of decay products and the derivation of related equations. Participants explore theoretical aspects and seek clarification on the mathematical formulations presented in external resources.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions whether the momenta of the two decay products are always equal, especially when the particles have different masses.
  • Another participant asserts that in the center of mass system, the momenta of the two decay products are equal and opposite, referencing a specific equation related to energy and momentum.
  • Several participants express confusion regarding the derivation of a specific equation (Equation 37.16) related to momentum, questioning how the terms in the square root are obtained.
  • There is a repeated request for clarification on the relationship between energy and momentum, particularly how the equation p = E - m is applied in this context.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the derivation of specific equations and the conditions under which certain momentum relationships hold. There is no consensus on the clarity of the derivations or the implications of mass differences on momentum.

Contextual Notes

Participants reference external resources for equations and transformations, indicating a reliance on those materials for understanding the kinematics involved. The discussion highlights potential gaps in the derivation process and assumptions made in the referenced equations.

planesinspace
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Hi, I am learning about analysing particles decaying and am on this Wikipedia article: http://en.wikipedia.org/wiki/Particle_decay

Under the 'Two body decay' subsection, there is a description of the momentum of particles 1 and 2 from the rest frame of the parent particle.

I have two questions, firstly, it states that the momentum of particle 1 is equal to the momentum of particle 2, is this always the case? If they are of different mass I would have thought the momentums might be different as well.

Secondly, they state the equation for the momentum of particle 1 (or 2) in terms of the masses of all particles involved. I'm assuming they derived this from the equations mentioned in the preceding section about four momentum, but I cannot see how they have got that final result. When I try to dervie the momentum of particle 1 (or 2), using the results from the preceding section, I end up with: p_1 = sqrt[m_parent^2 + m_2^2 - m_1^2 -m_2\ 2m_parent].

Is anyone able to explain where they got that result from?
Any help greatly appreciated
 
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In two-body decays, the momenta of the two decay products are always equal and opposite in the center of mass (CM) system of the decaying particle:
(pc)2 = E2 - (mc2)2.
Lorentz transformations to the lab system are performed using the transformation in Section 37.1 of

http://pdg.lbl.gov/2002/kinemarpp.pdf

Two-particle dacays are specifically discussed in Section 37.4.1

Bob S
 
Thanks for the link. Equation 37.16 is the one that I was having trouble with, and apologies for my ignorance but I still don't see how they arrived at that formula?

If p= E-m, then how do they arrive at that equation? I'm guessing the square root has something to do with getting the magnitude of the p vector, but where do those two terms in the square root come from?
 
planesinspace said:
Thanks for the link. Equation 37.16 is the one that I was having trouble with, and apologies for my ignorance but I still don't see how they arrived at that formula?

If p= E-m, then how do they arrive at that equation? I'm guessing the square root has something to do with getting the magnitude of the p vector, but where do those two terms in the square root come from?
Look at Equations (14) and (15) in

http://www.google.com/url?sa=t&sour...TC6ZYE&usg=AFQjCNFB_gFuNy0JYBlOZEzYMSSjBvxBwg

Bob S
 

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