Analytic Geometry - finding the normal vector at a point

In summary, you need a normal vector and a point to define a surface. You can get the normal vector by taking the gradient of the plane equation, but you need the specific one that goes through a known coordinate.
  • #1
cfphys
4
0
I'm struggling to find the method to use when trying to get the normal vector n to a (flat) surface at a specific point. Every textbook I've researched has the same scenerio, where they show how to get a plane given a point and normal vector, but I have the opposite problem, where I know the plane and know the point but want the normal. And since that method uses a dot product I can't simply "undo" it to find n.

I know how to get the general normal to the surface by taking the gradient of the plane equation, but I need the specific one that goes through a known coordinate.

And sorry to make it more difficult, but this is in cylindrical coordinates... if there is a way to do this without converting to Cartesian that would be some excellent information.

Thanks
 
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  • #2
I don't understand... that answer should just be that normal vector you have already found rooted at p. The normal vector has the same coordinates everywhere on the plane.

Your surface is just a mapping from (r, theta, z) to (x,y,z). If you cross-prod your two coordinate curves mapped into your set of xyz coordinates defining your surface, you get a normal vector in cartesian coordinates.

Maybe you can post the whole problem statement?
 
  • #3
Thanks 7thSon

I understand the idea that the normal is the same everywhere and that I just have to root it at the point p to obtain the equation of the line perpendicular to the surface passing through p, I guess I just don't know how to do that..? Let's say I have the general normal, how do I plug in p to make it a specific line?

Here's the scenario:

Dealing with ray optics, I have a beam incident on a prism. And to use Snell's Law I need to define the incident plane. To define that plane I need two vectors, one is the vector of the incident beam, and the other is the vector that's perpendicular to the surface of the prism at the point where the beam hits it.

Finding that vector is my priority, doing it in cylindrical is secondary, though it would be extremely useful, because there is more than one prism and they are all rotating and it's a big mess in Cartesian.
 
  • #4
I can define a vector field on all of [tex] R^3 [/tex] that is constant, e.g. F(x,y,z) = ( 1, 2 , -1). Therefore at any location in R3 you have an associated vector (1 , 2, -1). You can either claim a vector exists somewhere in a manifold like R3 or define a vector field on some set of space.

What you really want is a line, not a vector. More precisely what you want is a line(contour) whose tangent is a constant equal to that vector. There are infinite formulas/parameterizations for that line. One of them is to let [tex] t [/tex] parameterize your line and define C := (x0 + n1*t, y0 + n2*t, z0 + n3*t), where n = (n1, n2, n3) is your normal vector and P = (x0, y0, z0) is the coordinate of your point of interest. You can let t run from negative infinity to infinity or whatever interval you want. You can also pick another point (x1, y1,z1) such that the curve passes through that point at t = 0.

You could parameterize that curve in cylindrical coordinates but I doubt you would really want to.
 
  • #5


One method to find the normal vector at a specific point on a flat surface is to use the cross product. The cross product of two vectors will give you a vector that is perpendicular to both of the original vectors.

In this case, you can take any two vectors that lie on the plane at the specific point you are interested in and use the cross product to find the normal vector. For example, if you know the coordinates of three points on the plane (including the specific point you are interested in), you can use the cross product of the vectors formed by these points to find the normal vector.

Another method is to use the equation for a plane in cylindrical coordinates: ρcos(ϕ)x + ρsin(ϕ)y + z = d. In this equation, ρ and ϕ represent the cylindrical coordinates of a point on the plane, and d is a constant. By taking the gradient of this equation, you can find the normal vector at any point on the plane.

If you are still struggling to find the normal vector, I suggest consulting with a math or physics professor or seeking help from a tutor. They may be able to provide additional guidance and examples specific to your problem.
 

What is a normal vector in analytic geometry?

A normal vector is a vector that is perpendicular, or at a right angle, to a given line or surface at a specific point. It is used in analytic geometry to determine the direction of a line or surface at a given point.

How do you find the normal vector at a point on a line?

To find the normal vector at a point on a line, you must first find the slope of the line using the slope formula. Then, take the negative reciprocal of the slope to find the slope of the perpendicular line. This slope, along with the coordinates of the given point, can be used to create the normal vector.

What is the formula for finding the normal vector at a point on a surface?

The formula for finding the normal vector at a point on a surface is to take the partial derivatives of the surface equation with respect to each variable, and then use those derivatives as the components of the normal vector at the given point.

Why is finding the normal vector important in analytic geometry?

Finding the normal vector at a point is important in analytic geometry because it allows us to determine the direction at which a line or surface is pointing at that specific point. This information is useful in various applications, such as calculating the angle between two lines or determining the direction of a force acting on a surface.

Can the normal vector at a point change?

Yes, the normal vector at a point can change if the line or surface is not a straight line or a flat surface. In these cases, the normal vector will be different at different points along the line or surface. However, for a straight line or a flat surface, the normal vector will remain constant at all points.

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