Analyzing 2D Elastic Collisions with Varying Masses and Velocities

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SUMMARY

This discussion focuses on analyzing a 2D elastic collision involving a 1.0-kg particle and a 4.0-kg particle, where the former moves at 4.0 m/s and the latter at -1.0 m/s. The collision is characterized by the 1.0-kg particle deflecting at an angle of 130 degrees counterclockwise from the positive x-axis. Key equations utilized include momentum conservation and kinetic energy conservation, specifically m1*v1 = (m1*v3*cos(ø3)) + (m2*v4*cos(ø4)) and m1*v1^2 = (m1*(v3)^2) + (m2*(v4)^2). The discussion also raises the concept of analyzing the collision in a center-of-mass system due to the total momentum being zero.

PREREQUISITES
  • Understanding of 2D vector components in physics
  • Familiarity with elastic collision principles
  • Knowledge of momentum conservation laws
  • Ability to apply trigonometric functions in physics problems
NEXT STEPS
  • Study the derivation of the elastic collision equations in two dimensions
  • Learn about center-of-mass reference frames in collision analysis
  • Explore the application of trigonometric identities in resolving vector components
  • Investigate the effects of varying masses on collision outcomes in elastic collisions
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of elastic collisions in two dimensions, particularly those involving varying masses and velocities.

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Homework Statement



A 1.0-kg particle is moving in the +x direction at 4.0m/s when it collides elastically with a 4.0-kg particle moving in the −x direction at 1.0m/s After colliding the 1-kg particle moves off at 130 counterclockwise from the positive x-axis. Find the final speeds of both particles and the direction of the more massive one.

Homework Equations



m1*v1=(m1*v3*cos(ø3))+(m2*v4*cos(ø4))

0=(m2*v4*sinø4)-(m1*v3*sin(ø3))

m1*v1^2 = (m1*(v3)^2) + (m2*(v4)^2)

The Attempt at a Solution



(1 kg)(4i m/s) + (4 kg)(-1i m/s) = 0 ==> The total momentum=0

Is there some sort of trick that can be used for 2 dimensional elastic collisions when the masses and speeds swap? Also, since the total momentum is 0, can it be specified as a center-of-mass system, thus being able to use the scattering angle? Thanks in advance for any help!
 
Physics news on Phys.org
Hello poolec4. Welcome to PF!

What is the total momentum vector after the collision?

What does that tell you about the magnitudes and the relative directions of the individual final momenta?
 

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