How Is Angular Acceleration Calculated for a Rotating Door?

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To calculate the angular acceleration of a rotating door made of four rectangular glass panes, one must consider torque and moment of inertia rather than linear force and mass. The initial approach using linear acceleration was incorrect. The correct method involves determining the moment of inertia of the door and relating torque to angular acceleration. The discussion emphasizes the importance of understanding these rotational dynamics concepts to solve the problem accurately. A clear understanding of torque and moment of inertia is essential for calculating angular acceleration in this scenario.
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1. rotating door is made from four rectangular glass panes, as shown in the drawing. The mass of each pane is 95 kg. A person pushes on the outer edge of one pane with a force of F = 80 N that is directed perpendicular to the pane. Determine the magnitude of the door's angular acceleration.

The with of each pane to the rotation axis is 1.2m



This is how I approached it

F=ma
a= f/m =80/95 = 0.84

Now Tangential Acceleration a = angular acceleration x radius

angular acceleration = tangential acceleration/radius

= 0.84/1.2 = 0.70 rad/m^2

this answer was wrong



The Attempt at a Solution

 
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Since the movement is rotational, you should use torque and momentum of inertia, instead of force and mass.
 
SGT said:
Since the movement is rotational, you should use torque and momentum of inertia, instead of force and mass.


How do I do that? Where do i start? please hep
 
Well, what do you know about torque and moment of inertia? In particular, do you know how to relate torque to the angular acceleration?
 
no. I don't
 
Well firstly you need to work out the moment of inertia of the door. Could you explain more precisely what the diagram looks like? Do you know what the moment of inertia is? Do you know how to find the moment of inertia of a solid object? Have you come across anything in your textbook relating it and the torque to the angular acceleration?

As an aside, in response to your pm, I'm sorry-- I can't keep track of every thread I help in.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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