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Angular acceleration spin-dry cycle

  1. Oct 17, 2006 #1
    Just checking to see fi I did the math right:

    During the spin-dry cycle of a wash, the motor slows down from 95 rad/s to 30 rad/s while turning the drum through an angle of 402 radians. What is the magnitude of the angular acceleration of the motor?

    = 1/2(Wo + W)t
    402 = 1/2(95 + 30)t
    402 = 62.5t
    6.4 = t

    ang. accel. = W - Wo / t - to
    = 30 - 95 / 6.4
    = 10 rad/s^2
     
  2. jcsd
  3. Oct 17, 2006 #2
    Looks good to me.
     
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