brncsfns5621
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Just checking to see fi I did the math right:
During the spin-dry cycle of a wash, the motor slows down from 95 rad/s to 30 rad/s while turning the drum through an angle of 402 radians. What is the magnitude of the angular acceleration of the motor?
= 1/2(Wo + W)t
402 = 1/2(95 + 30)t
402 = 62.5t
6.4 = t
ang. accel. = W - Wo / t - to
= 30 - 95 / 6.4
= 10 rad/s^2
During the spin-dry cycle of a wash, the motor slows down from 95 rad/s to 30 rad/s while turning the drum through an angle of 402 radians. What is the magnitude of the angular acceleration of the motor?
= 1/2(Wo + W)t
402 = 1/2(95 + 30)t
402 = 62.5t
6.4 = t
ang. accel. = W - Wo / t - to
= 30 - 95 / 6.4
= 10 rad/s^2