Angular Frequency Change with Mouse Movement on Wagon Wheel

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Homework Statement



a mouse is rinding on the rim of a 2.0kg wagon wheel that rotates freely in a horizontal plane at an angular frequency of 1.00 revs/sec. after riding there for a while, the mouse runs into the center, axis, of the wheel. the mass of mouse is 0.1kg and assume that all of the mass of the wheel is concentrated around the rim. what is the new angular frequency when the mouse reaches the axis?

Homework Equations


ok i know that [tex]\omega[/tex] is directly proportional to the freq. which is the angular frequency.
[tex]\omega[/tex]=2(pi)/T


The Attempt at a Solution


using the equation for omega, 2(pi)/1 equals 6.28319. is that my new angular freq.? i don't understand what to use?
 
hint: what quantity is conserved in the problem?
 
i don't understand what is concerved? heeeeeeeelllp? lol
 

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