Angular Frequency Change with Mouse Movement on Wagon Wheel

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SUMMARY

The discussion centers on calculating the new angular frequency of a 2.0 kg wagon wheel when a 0.1 kg mouse moves from the rim to the center. Initially, the wheel rotates at an angular frequency of 1.00 revs/sec, which translates to an angular velocity (ω) of approximately 6.28319 rad/sec. The conservation of angular momentum is the key principle in this scenario, indicating that the initial angular momentum must equal the final angular momentum. Thus, the new angular frequency can be determined using the formula for angular momentum conservation.

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Homework Statement



a mouse is rinding on the rim of a 2.0kg wagon wheel that rotates freely in a horizontal plane at an angular frequency of 1.00 revs/sec. after riding there for a while, the mouse runs into the center, axis, of the wheel. the mass of mouse is 0.1kg and assume that all of the mass of the wheel is concentrated around the rim. what is the new angular frequency when the mouse reaches the axis?

Homework Equations


ok i know that \omega is directly proportional to the freq. which is the angular frequency.
\omega=2(pi)/T


The Attempt at a Solution


using the equation for omega, 2(pi)/1 equals 6.28319. is that my new angular freq.? i don't understand what to use?
 
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hint: what quantity is conserved in the problem?
 
i don't understand what is concerved? heeeeeeeelllp? lol
 

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