Angular motion of a car wheel traveling at certain speed

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SUMMARY

The discussion centers on calculating the angular displacement of a car wheel accelerating from 7 revolutions per second (rev/s) to 14 rev/s over a period of 5 seconds. Participants clarify that 7 rev/s translates to 14π radians, and the correct approach involves using the average angular velocity to find displacement. The average angular velocity is calculated as θ = 1/2 (ω₁ + ω₀)t, leading to a displacement of 330 radians. The acceleration is determined to be 8.8 rad/s², confirming the calculations provided by the participants.

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inuka00123
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Homework Statement
a car is travelling at certain speed, wheels are circling 7 rounds per second, after some time it accelerates in 5 second to twice the speed before, how much angular displacement the wheel has during 5 seconds of acceleration
Relevant Equations
ω = θ/t, α = ω/t
I assumed first the car is travelling 7 rad/s then accelerated to 14 rad/s in 5 seconds, after plugging the variables, I got θ = 35, I must be wrong about this calculation, can someone explain, if wrong give me the way of calculation please?
 
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7 rounds per second means seven revolutions, not seven radians ...

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New PF user has been reminded that we do not give answers and that they need to show their work.
yeah, I saw that it means I need to multiply it by 2pi to get to the radians, can you give me the answer for this question, it would help me to compare my solution and what is correct to find what I am missing more
BvU said:
7 rounds per second means seven revolutions, not seven radians ...

##\ ##
 
inuka00123 said:
I assumed first the car is travelling 7 rad/s then accelerated to 14 rad/s in 5 seconds, after plugging the variables, I got θ = 35,
Can you show your work for this? Just giving us the final answer will not tell us where you went wrong.

If the wheels are turning at 7 rad/s and keep turning for 5 seconds then even without any acceleration they will rotate through 35 radians in 5 seconds.

So you need to add in the acceleration somehow. There are a couple of ways to think about doing that. One way would be to get the average rotation rate.
 
inuka00123 said:
yeah, I saw that it means I need to multiply it by 2pi to get to the radians, can you give me the answer for this question, it would help me to compare my solution and what is correct to find what I am missing more
You will need another relevant equation. Can you show it ?

##\ ##
 
BvU said:
jbriggs444 said:
Can you show your work for this? Just giving us the final answer will not tell us where you went wrong.

If the wheels are turning at 7 rad/s and keep turning for 5 seconds then even without any acceleration they will rotate through 35 radians in 5 seconds.

So you need to add in the acceleration somehow. There are a couple of ways to think about doing that. One way would be to get the average rotation rate.
I am sorry, but as BvU stated it is not 7rad/s but 7 revolutions and 14 revolutions. the question I asked is wrong
 
Last edited:
jbriggs444 said:
Can you show your work for this? Just giving us the final answer will not tell us where you went wrong.

If the wheels are turning at 7 rad/s and keep turning for 5 seconds then even without any acceleration they will rotate through 35 radians in 5 seconds.

So you need to add in the acceleration somehow. There are a couple of ways to think about doing that. One way would be to get the average rotation rate.
is it wrong to just use the θ = revolutions per second x 2π, after plugging the equations,

θ₁ = rev x 2π
= 7 x 2π
= 44 radians

θ₂ = rev x 2π
= 14 x 2π
= 88 radians

*to get the θ between acceleration I subtract θ₁ from θ₂, and got 44 radians. when the acceleration come into this equation, I do not understand.
 
Last edited:
inuka00123 said:
is it wrong to just use the θ = revolutions per second x 2π, after plugging the equations,

θ₁ = rev x 2π
= 7 x 2π
= 44 radians

θ₂ = rev x 2π
= 14 x 2π
= 88 radians

*to get the θ between acceleration I subtract θ₁ from θ₂, and got 44 radians. when the acceleration come into this equation, I do not understand.π
This post shows that you are confused. You are given an initial angular speed of 7 revolutions per second. This means that if this number does not change, for every second that goes by, the wheel makes 7 revolutions or turns by an angle of 7×2π = 14π radians. However, here the wheel is speeding up because after 5 seconds have gone by, we are told that the speed has doubled. If the speed changes, the wheel is accelerating.

Can you find the acceleration given that the angular speed increases from 7 revolutions per second to 14 revolutions per second?
If so, were you taught the kinematic equations relating acceleration and displacement?
 
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kuruman said:
Can you find the acceleration given that the angular speed increases from 7 revolutions per second to 14 revolutions per second?
Or, another approach, can you (@inuka00123) find the average angular speed over the interval?
 
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  • #10
I am really confused, if I find the acceleration using ω₁ = ω₀ + at equation and plug that onto another equation or I can just use the θ = 1/2 (ω₁ + ω₀)t equation, right?, my textbook is really confusing, and 1/2 (ω₁ + ω₀) would be the average speed, or avg angular velocity, or angular speed I suppose
 
  • #11
inuka00123 said:
I am really confused, if I find the acceleration using ω₁ = ω₀ + at equation and plug that onto another equation or I can just use the θ = 1/2 (ω₁ + ω₀)t equation, right?, my textbook is really confusing, and 1/2 (ω₁ + ω₀) would be the average speed, or avg angular velocity, or angular speed I suppose
Either way you will get the same answer if you do it right. Using the average angular velocity as @jbriggs444 suggested is more straightforward. Try it that way, get a number and post your solution. Then try it the other way using the acceleration. If the numbers are the same, you will have learned something and perhaps be less confused.
 
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  • #12
I tried different equations, every one seems give a = 8.8 rad/s² and for displacement 330 radians, because I tried to plug the answer to different equations and got the same solution, I think it is correct, thank you!
 
  • #13
I agree with your numbers.
 
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