Angular speed vs. Orbital speed

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The discussion focuses on calculating the Earth's angular speed and orbital speed around the sun. The angular speed is determined using the formula ω=Δθ/T, resulting in a value of approximately 1.99x10^-7 radians/sec. The orbital speed is calculated in linear terms, yielding a speed of about 29,806.08 m/s. Participants confirm that the conversion from radians to meters depends on the radius of the orbit. The conversation emphasizes the importance of correct unit conversion in these calculations.
austindubose
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Homework Statement


Consider a year to be precisely 365 days. Determine the angular speed of the Earth about the sun. If the Earth's mean distance from the sun is 1.496x1011 meters and our orbit is circular, determine our orbital speed about the sun.


Homework Equations


ω=Δθ/T, where ω is the average angular velocity, Δθ is the distance around a circle (in radians) traveled, and T is the period of orbit.


The Attempt at a Solution


Using the formula mentioned above, I found the angular speed to be 1.99x10-7 radians/sec, and I Googled the answer and found that this answer seems to be right (please correct me if I am still wrong). Would the orbital speed be the same idea expressed in a linear fashion (i.e., 29,806.08 m/s)?

Thanks for all your help yet again!
 
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Yes, all you would have to do is make the unit conversion from radians to metres. This would of course depend on the radius of the orbit.
 
Thank you very much! I appreciate the quick reply
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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