The problem involves calculating the angular velocity of bicycle wheels given the cyclist's speed and the wheel's diameter. The subject area pertains to angular kinematics and the relationship between linear and angular motion.
Participants are actively engaging with the problem, sharing their attempts and questioning their understanding of the concepts involved. Some guidance has been offered regarding the relationship between linear and angular speed, but no consensus has been reached on the solution.
There is confusion regarding the conversion of units and the application of relevant equations. Participants express uncertainty about their calculations and the definitions they are using.
Welcome to Physics Forums.bionut said:Homework Statement
A cyclist is traveling at a speed of 30km/hr. If the diameter of the bike wheel is 0.70 meter, what is the angular velocity of the wheels in rad/sec?
Homework Equations
The Attempt at a Solution
Hi, I have racked my brain trying ot work this out, I know the answer is 23.7 rad/sec
(but I don't know hoe to get there ;-(!
All I could come up with is 0.83m/s=speed and r=0.07m
Almost, the definition of angular velocity (or speed) should be in your notes or textbook. Perhaps you could look it up.bionut said:okay, not sure if I am thinking is on the right track, but would the angular speed be in reference to revolutions/time period? Where 1 revolution - 2(pi)r?
You're looking for something that related linear speed to angular speed. See, for example, here: http://hyperphysics.phy-astr.gsu.edu/hbase/rotq.html#avelbionut said:okay, all it says is angular speed = angular distance / change in time
Not quite. 30 km/hr is 8.33... m/s. So, the equation you need isbionut said:Okay, thankyou for your help... but I am back to sqaure 1 lol... gawd !
okay if v=wr and s=2pi and the displacmeent is 2pi (6.8 rad) X 0.70 = 4.40, and v=30km/hr , is the tangential velcoity 0.83m/s