A girl swings back and forth on a swing with ropes that are 4.00 m long. The maximum height she reaches is 2 m above the ground. At the lowest point of the swing she is .5 m above the ground. (a) The girl attains the maximum speed (1)at the top, (2) in the middle, (3) at the bottom of the swing. Why? (b) What is the girl's maximum speed?(adsbygoogle = window.adsbygoogle || []).push({});

I think 1/2mv^2=mghmax then the M would cancel leaving 1/2v^2=ghmax. Then I ended up with v=square root of 2ghmax.

Well using that equation I keep getting 3.13 m/sec for the lowest point(.5 m) and 6.26 m/sec for the highest point(2 m). The answers are the bottom since the lower the potential energy the higher the kinetic energy. And the other answer is 5.42 m/sec. I'm pretty lost on this one...

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# Homework Help: Another easy Conservation of Energy Question

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