- #1

XxMuDvAyNexX

- 21

- 0

I think 1/2mv^2=mghmax then the M would cancel leaving 1/2v^2=ghmax. Then I ended up with v=square root of 2ghmax.

Well using that equation I keep getting 3.13 m/sec for the lowest point(.5 m) and 6.26 m/sec for the highest point(2 m). The answers are the bottom since the lower the potential energy the higher the kinetic energy. And the other answer is 5.42 m/sec. I'm pretty lost on this one...