MHB Answer: Image Direct Sum & Linear Operator: Is Union Equal?

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The image of the direct sum of two subspaces under a linear operator is not equal to the union of the images of the subspaces. A counterexample using the identity operator on V = R² demonstrates this, where the direct sum of subspaces X and Y does not yield the same result as the union of their images. Instead, the correct relationship is that the image of the direct sum equals the sum of the images under the operator. This distinction is crucial for understanding linear transformations and their effects on subspaces. Thus, the statement about the union being equal is false.
Fermat1
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Given 2 subspaces and a linear operator, is the image of the direct sum of the subspaces equal to the union of the images under the operator?

Thanks
 
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Fermat said:
Given 2 subspaces and a linear operator, is the image of the direct sum of the subspaces equal to the union of the images under the operator?

Thanks
This is not true.

For a counterexample:
Let $V=\mathbb R^2$ and $X=\{(x,0):x\in\mathbb R\}$ and $Y=\{(0,y):y\in\mathbb R\}$.

Then $X$ and $Y$ are subspaces of $V$.

Let $I$ be the identity operator on $V$.

You can see that $I(X\oplus Y)\neq I(X)\cup I(Y)$.To make your statement true you can have:
Given 2 subspaces of a vector space $V$ and a linear operator on $V$, the image of the direct sum of the subspaces is equal to the sum of the images under the operator.
 
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