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## Main Question or Discussion Point

I have read somewhere: Any decimal number in the range

I suspect it's wrong. Shouldn't it rather be 0 to [(2^n)-1]?

Please guide me. Thanks.

**0 to 2^(n-1)**can be represented in binary form as an n-bit number.I suspect it's wrong. Shouldn't it rather be 0 to [(2^n)-1]?

Please guide me. Thanks.