Any idea for this nonlinear equation?

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Discussion Overview

The discussion revolves around a nonlinear partial differential equation (PDE) related to the diffusion of multiphase fluids in porous media. Participants explore potential solutions, both analytical and semi-analytical, and clarify the formulation of the equation.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant presents a nonlinear PDE for capillary pressure diffusion and seeks solutions.
  • Another participant requests clarification on the equation's variables and structure.
  • A proposed form of the PDE is shared, but it is noted that finding a general solution may be challenging.
  • Specific particular solutions are suggested, including forms involving hyperbolic tangent and exponential functions.
  • A later reply questions the validity of the proposed solutions, stating they do not represent a general solution and are not orthogonal.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the proposed solutions, with some expressing skepticism about their validity and others attempting to clarify the equation's structure.

Contextual Notes

There are unresolved aspects regarding the generality of the proposed solutions and their mathematical properties, such as orthogonality.

fery
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Hi

I have a nonlinear equation for diffusion of multiphase fluids in porous media, and it is like
1/2(Laplacian(P^2)+d(p)/dy=d(p)/dt
I couldn't find any analytical or semianalytical solution for this equation, do you have any idea?
 
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Can you write out your DE more clearly. Independent and dependent (P and/or p) variables first of all.
 
Sure, P = P(x,y,t), Laplacian = d/dx2 + d/dy2, As I said this nonlinear equation represents diffusion of capillary pressure in porous media.
 
If I understand rightly, your PDE is

[tex]\frac{1}{2}(\frac{\partial^2 P^2}{\partial x^2}+\frac{\partial^2 P^2}{\partial y^2})+\frac{\partial P}{\partial y}=\frac{\partial P}{\partial t}[/tex]

I do not think that it is easy to find the general solution to the PDE, but you can find some particular solutions of the type

[tex]P = \frac{1}{C_5 +C_6 \tanh(C_1+C_2 x+iC_2 (y+t))}[/tex]

[tex]P = \frac{\sqrt{2}}{k}e^{-\frac{kx}{2}}\sqrt{e^{2kx}C_1 -C_2 }\sqrt{C_3 \sin[k(y+t)]-C_4 \cos[k(y+t)]}[/tex]
 
Last edited:
Thanks you, I am not quite sure about the second type, can you fix the Parenthesis.
 
[tex]P = \frac{1}{C_5 +C_6 \tanh[C_1+C_2 x+iC_2 (y+t)]}[/tex]

[tex]P = \frac{\sqrt{2}}{k}e^{-\frac{kx}{2}}\sqrt{e^{2kx}C_1 -C_2 }\sqrt{C_3 \sin[k(y+t)]-C_4 \cos[k(y+t)]}[/tex]
 
kosovtsov said:
[tex]P = \frac{1}{C_5 +C_6 \tanh[C_1+C_2 x+iC_2 (y+t)]}[/tex]

[tex]P = \frac{\sqrt{2}}{k}e^{-\frac{kx}{2}}\sqrt{e^{2kx}C_1 -C_2 }\sqrt{C_3 \sin[k(y+t)]-C_4 \cos[k(y+t)]}[/tex]

Since your in such an advanced math and know a lot about it, does that make sense when you look at it? I mean is it hard for you or scary? if you understand what i mean i know its a sill question and maybe for this thread.
 
If you are asking me, I don't think these functions represent the general solution of the equation. And they are not orthogonal so if they would be the general solution, we would never be able to find particular solution for them.
 

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